4=0.02w^2

Solution for 4=0.02w^2 equation:

4=0.02w^2

We move all terms to the left:

4-(0.02w^2)=0

We get rid of parentheses

-0.02w^2+4=0

a = -0.02; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-0.02)·4
Δ = 0.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.32}}{2*-0.02}=\frac{0-\sqrt{0.32}}{-0.04}
=-\frac{\sqrt{}}{-0.04}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.32}}{2*-0.02}=\frac{0+\sqrt{0.32}}{-0.04}
=\frac{\sqrt{}}{-0.04}
$